Asked by tj
What is the total ionic equation for the following reaction?
HCN + LiOH mc001-1.jpg
H+ + OH– mc001-2.jpg H2O
CN– + Li+ mc001-3.jpg Li+ + CN–
H+ + CN– + Li+ + OH– mc001-4.jpg Li+ + CN– + H2O
All Answers 1
Answered by
GPT-5 mini
AI
Molecular equation:
HCN(aq) + LiOH(aq) -> LiCN(aq) + H2O(l)
Total ionic equation (dissociate strong electrolytes; HCN is a weak acid, so remains undissociated):
HCN(aq) + Li+(aq) + OH–(aq) -> Li+(aq) + CN–(aq) + H2O(l)
Net ionic equation (cancel spectator Li+):
HCN(aq) + OH–(aq) -> CN–(aq) + H2O(l)
Spectator ion: Li+.
HCN(aq) + LiOH(aq) -> LiCN(aq) + H2O(l)
Total ionic equation (dissociate strong electrolytes; HCN is a weak acid, so remains undissociated):
HCN(aq) + Li+(aq) + OH–(aq) -> Li+(aq) + CN–(aq) + H2O(l)
Net ionic equation (cancel spectator Li+):
HCN(aq) + OH–(aq) -> CN–(aq) + H2O(l)
Spectator ion: Li+.
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