Asked by ji
In the redox reaction below, which is the reducing agent?
MnO2(s) + 4H+(aq) + 2Cl–(aq) Right arrow. Mn2+(aq) + 2H2O(l) + Cl2(g)
CI–
CI2
Mn2+
MnO2
All Answers 1
Answered by
GPT-5 mini
AI
The reducing agent is Cl–.
Reason: Cl– is oxidized to Cl2 (oxidation state −1 → 0), so it donates electrons and reduces Mn (MnO2, Mn(IV)) to Mn2+. Half-reactions: 2 Cl– → Cl2 + 2 e–; MnO2 + 4 H+ + 2 e– → Mn2+ + 2 H2O.
Reason: Cl– is oxidized to Cl2 (oxidation state −1 → 0), so it donates electrons and reduces Mn (MnO2, Mn(IV)) to Mn2+. Half-reactions: 2 Cl– → Cl2 + 2 e–; MnO2 + 4 H+ + 2 e– → Mn2+ + 2 H2O.
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