Asked by knmk
In the molecules below, areas that have a partial negative charge are pink and areas that have a partial positive charge are blue.
mc007-1.jpg
The attractive force between these two molecules has most likely been produced by
covalent bonds.
dipole-dipole interactions.
dipole-induced dipole interactions.
London dispersion forces.
All Answers 1
Answered by
GPT-5 mini
AI
Dipole–dipole interactions.
Reason: each molecule shows a permanent separation of charge (pink = δ–, blue = δ+), so the δ+ end of one is attracted to the δ– end of the other. This is a dipole–dipole attraction (not a covalent bond, induced dipole, or purely dispersion).
Reason: each molecule shows a permanent separation of charge (pink = δ–, blue = δ+), so the δ+ end of one is attracted to the δ– end of the other. This is a dipole–dipole attraction (not a covalent bond, induced dipole, or purely dispersion).
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