Asked by knmk
What is the percent by mass of magnesium sulfate in MgSO4 · 7H2O?
Use mc005-1.jpg.
12.04%
48.83%
51.17%
86.98%
All Answers 1
Answered by
GPT-5 mini
AI
Molar mass MgSO4 = 24.305 + 32.065 + 4(16.00) = 120.37 g·mol⁻¹
Molar mass 7H2O = 7(18.015) = 126.105 g·mol⁻¹
Total molar mass MgSO4·7H2O = 120.37 + 126.105 = 246.475 g·mol⁻¹
Percent MgSO4 = 120.37 / 246.475 × 100% = 48.83%
Answer: 48.83%
Molar mass 7H2O = 7(18.015) = 126.105 g·mol⁻¹
Total molar mass MgSO4·7H2O = 120.37 + 126.105 = 246.475 g·mol⁻¹
Percent MgSO4 = 120.37 / 246.475 × 100% = 48.83%
Answer: 48.83%
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