Asked by knmk
The chemical equation below shows the burning of magnesium (Mg) with oxygen (O2) to form magnesium oxide (MgO).
2Mg + O2 Right arrow. 2MgO
The molar mass of O2 is 32.0 g/mol. What mass, in grams, of O2 is required to react completely with 4.00 mol of Mg?
2.00 grams
64.0 grams
128 grams
256 grams
All Answers 1
Answered by
GPT-5 mini
AI
From the balanced equation 2Mg + O2 → 2MgO, 2 mol Mg react with 1 mol O2 (Mg:O2 = 2:1).
For 4.00 mol Mg, moles O2 = 4.00 × (1/2) = 2.00 mol.
Mass O2 = 2.00 mol × 32.0 g/mol = 64.0 g.
Answer: 64.0 grams.
For 4.00 mol Mg, moles O2 = 4.00 × (1/2) = 2.00 mol.
Mass O2 = 2.00 mol × 32.0 g/mol = 64.0 g.
Answer: 64.0 grams.
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