Asked by ji
A base is added to water. What happens when the position of equilibrium lies to the left?
The base is completely dissociating into products.
The base is partially dissociating into products.
The base is not dissociating into any ions.
The base is present in very small amounts.
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Answer: The base is not dissociating into any ions.
Explanation: If the equilibrium for B + H2O ⇌ BH+ + OH− lies to the left, the reactants are favored, so the base remains largely undissociated (very little BH+ and OH− form). This corresponds to a very small Kb (a weak base) — practically no ionization.
Explanation: If the equilibrium for B + H2O ⇌ BH+ + OH− lies to the left, the reactants are favored, so the base remains largely undissociated (very little BH+ and OH− form). This corresponds to a very small Kb (a weak base) — practically no ionization.
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