Question

1. Applying Concepts Look at Figure 14-2.
If Machine A moves through an input
distance of 4.0 m, what is the output
distance of Machine B?
2. Classifying What type of simple machine
is Machine A in Figure 14-2?
3. Interpreting Graphics What is the IMA
of Machine B in Figure 14-2?
4. Interpreting Graphics As shown in
Figure 14-2, Machines A and B operate
together as what type of machine?
5. Comparing and Contrasting In Figure
14-2, how does the work input of
Machine B compare with the work
output of Machine A?
Problem
Write the answers to each question on a separate sheet of paper.
1. A worker uses a cart to move a load of bricks weighing 680 N a
distance of 10 m across a parking lot. If he pushes the cart with a
constant force of 220 N, what amount of work does he do? Show
your work.
2. A girl lifts a 100-N load a height of 2.0 m in a time of 0.5 s. What
power does the girl produce? Show your work.
3. The input force of a pulley system must move 6.0 m to lift a 3000-
N engine a distance of 0.50 m. What is the IMA of the system?
Show your work.
4. A 16-N force applied to the handle of a door produces a 30-N
output force. What is the AMA of the handle? Show your work.
5. A force of 12 N is applied to the handle of a screwdriver being
used to pry off the lid of a paint can. As the force moves through a
distance 0.3 m, the screwdriver does 32 J of work on the lid. What
is the efficiency of the screwdriver? Show your work.

Answer 1

I can’t answer questions 1–5 about Figure 14-2 without the figure (or a description of the machines and how they’re connected). Please upload the figure or describe Machines A and B (type of machine, how they’re linked, any labeled distances/forces), and I’ll answer those.

Meanwhile, here are the solutions (with work shown) for the numbered problems you gave:

Problem 1
A worker pushes with F = 220 N for distance d = 10 m.
Work W = F × d = 220 N × 10 m = 2200 J.

Answer: 2200 J

Problem 2
Load weight (force) = 100 N, lifted h = 2.0 m in t = 0.5 s.
Work = F × d = 100 N × 2.0 m = 200 J.
Power P = Work / time = 200 J / 0.5 s = 400 W.

Answer: 400 W

Problem 3
Input distance = 6.0 m, output (lift) distance = 0.50 m.
IMA = input distance / output distance = 6.0 m / 0.50 m = 12.

Answer: IMA = 12

Problem 4
Input force = 16 N, output force = 30 N.
AMA = Fout / Fin = 30 N / 16 N = 1.875 ≈ 1.88.

Answer: AMA ≈ 1.88

Problem 5
Input force = 12 N, input distance = 0.3 m → input work Win = 12 N × 0.3 m = 3.6 J.
Output work Wout = 32 J (given).
Efficiency η = (Wout / Win) × 100% = (32 J / 3.6 J) × 100% ≈ 888.9%.

This efficiency >100% is physically impossible, so the given numbers are inconsistent. Likely there is a typo in the problem (for example, if the screwdriver did 3.2 J of work, then η = (3.2 / 3.6)×100% ≈ 88.9%). Please check the problem statement and confirm the intended output work value.

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Send the Figure 14-2 image or a description and I’ll answer the first five figure-based questions.