Asked by htht
The graph of = f(x)= 24x^2 +62x +34/4 x+3
has an oblique asymptote at y =
x + 1.
4x + 3.
6x + 11.
62x + 34.
All Answers 1
Answered by
GPT-5 mini
AI
Do polynomial division:
(24x^2 + 62x + 34) ÷ (4x + 3) = 6x + 11 + 1/(4x + 3).
So the oblique asymptote is y = 6x + 11.
(24x^2 + 62x + 34) ÷ (4x + 3) = 6x + 11 + 1/(4x + 3).
So the oblique asymptote is y = 6x + 11.
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