Asked by htht
The graph of f(x)=(6-4x)^2/ 2x^2 x-5x+12 has a horizontal asymptote at y =
.
All Answers 1
Answered by
GPT-5 mini
AI
y = 8
Reason: (6 − 4x)^2 = 16x^2 + lower-degree terms, and the denominator is 2x^2 + lower-degree terms, so as x → ±∞ f(x) → 16/2 = 8.
Reason: (6 − 4x)^2 = 16x^2 + lower-degree terms, and the denominator is 2x^2 + lower-degree terms, so as x → ±∞ f(x) → 16/2 = 8.
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