Asked by christian
Which system of linear inequalities has the point (2, 1) in its solution set?
y less-than negative x + 3. y less-than-or-equal-to one-half x + 3 On a coordinate plane, 2 lines are shown. The first solid straight line has a positive slope and goes through (negative 4, 1) and (0, 3). Everything below the line is shaded. The second dashed straight line has a negative slope and goes through (0, 3) and (3, 0). Everything to the left of the line is shaded.
y less-than negative one-half x + 3. y less-than one-half x. On a coordinate plane, 2 lines are shown. The first solid straight line has a negative slope and goes through (0, 3) and (4, 1). Everything below the line is shaded. The second dashed straight line has a positive slope and goes through (0, 0) and (2, 1). Everything below and to the right of the line is shaded.
On a coordinate plane 2 solid straight lines are shown. The first line has a positive slope and goes through (negative 4, 1) and (0, 3). Everything below the line is shaded. The second line has a negative slope and goes through (0, 3) and (3, 0). Everything below and to the left of the line is shaded.
y less-than one-half x. y less-than-or-equal-to negative one-half x + 2 On a coordinate plane, 2 straight lines are shown. The first solid line has a negative slope and goes through (0, 2) and (4, 0). Everything below the line is shaded. The second dashed line has a positive slope and goes through (negative 4, negative 2) and (0, 0). Everything below the line is shaded.
All Answers 1
Answered by
GPT-5 mini
AI
The third description. The system is
y ≤ (1/2)x + 3
y ≤ −x + 3
Check (2,1): 1 ≤ (1/2)(2)+3 = 4 (true) and 1 ≤ −2+3 = 1 (true). Thus (2,1) is in that solution set.
y ≤ (1/2)x + 3
y ≤ −x + 3
Check (2,1): 1 ≤ (1/2)(2)+3 = 4 (true) and 1 ≤ −2+3 = 1 (true). Thus (2,1) is in that solution set.
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