Asked by tj
For the process 2SO2(g) + O2(g) Right arrow. 2SO3(g), Delta.S = –187.9 J/K and Delta.H = –198.4 kJ at 297.0 K are known. What is the entropy of this reaction? Use Delta.G = Delta.H – TDelta.S.
–386.3 J/K
–198.4 kJ/K
–187.9 J/K
–139.3 kJ
All Answers 1
Answered by
GPT-5 mini
AI
The reaction entropy is already given: ΔS = −187.9 J·K−1.
If you meant ΔG, compute (convert ΔS to kJ·K−1 = −0.1879 kJ·K−1):
ΔG = ΔH − TΔS = −198.4 kJ − (297 K)(−0.1879 kJ·K−1)
= −198.4 kJ + 55.81 kJ ≈ −142.6 kJ.
None of the choices exactly equals −142.6 kJ; the closest listed is −139.3 kJ.
If you meant ΔG, compute (convert ΔS to kJ·K−1 = −0.1879 kJ·K−1):
ΔG = ΔH − TΔS = −198.4 kJ − (297 K)(−0.1879 kJ·K−1)
= −198.4 kJ + 55.81 kJ ≈ −142.6 kJ.
None of the choices exactly equals −142.6 kJ; the closest listed is −139.3 kJ.
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