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What is the new concentration?
M NaCl
All Answers 1
Answered by
GPT-5 mini
AI
I don’t have enough information to compute a new concentration. Tell me either:
- the initial concentration and the volumes before and after dilution (or how much solvent you added), or
- the concentrations and volumes of two (or more) solutions you mixed.
Useful formulas:
1) For simple dilution of one solution:
C1·V1 = C2·V2 → C2 = C1·V1 / V2
(Use the same volume units for V1 and V2, e.g., mL or L.)
2) For mixing different solutions:
total moles = Σ(Ci·Vi) → Cfinal = total moles / Vtotal
Examples:
- Dilution example: 1.50 M NaCl, 50.0 mL diluted to 250.0 mL → C2 = (1.50·50.0)/250.0 = 0.300 M.
- Mixing example: 100.0 mL of 0.500 M mixed with 200.0 mL of 1.00 M → moles = 0.100·0.500 + 0.200·1.00 = 0.25 mol; Vtotal = 0.300 L → Cfinal = 0.25/0.300 = 0.833 M.
Give me the numbers you have and I’ll compute the new [NaCl].
- the initial concentration and the volumes before and after dilution (or how much solvent you added), or
- the concentrations and volumes of two (or more) solutions you mixed.
Useful formulas:
1) For simple dilution of one solution:
C1·V1 = C2·V2 → C2 = C1·V1 / V2
(Use the same volume units for V1 and V2, e.g., mL or L.)
2) For mixing different solutions:
total moles = Σ(Ci·Vi) → Cfinal = total moles / Vtotal
Examples:
- Dilution example: 1.50 M NaCl, 50.0 mL diluted to 250.0 mL → C2 = (1.50·50.0)/250.0 = 0.300 M.
- Mixing example: 100.0 mL of 0.500 M mixed with 200.0 mL of 1.00 M → moles = 0.100·0.500 + 0.200·1.00 = 0.25 mol; Vtotal = 0.300 L → Cfinal = 0.25/0.300 = 0.833 M.
Give me the numbers you have and I’ll compute the new [NaCl].
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