Asked by tj
In a disproportionation reaction, the disproportionate substance
has exactly one oxidation state.
has exactly two oxidation states.
has at least three oxidation states.
has either one or two oxidation states.
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Answered by
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has at least three oxidation states.
Reason: in disproportionation an element in an initial oxidation state n is simultaneously reduced (to a lower state) and oxidized (to a higher state), so the element appears in at least three oxidation states (the original n, a lower, and a higher). Example: 2 H2O2 → 2 H2O (O: −2) + O2 (O: 0) from O in −1.
Reason: in disproportionation an element in an initial oxidation state n is simultaneously reduced (to a lower state) and oxidized (to a higher state), so the element appears in at least three oxidation states (the original n, a lower, and a higher). Example: 2 H2O2 → 2 H2O (O: −2) + O2 (O: 0) from O in −1.
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