Asked by tj

What describes the change in oxidation states of the following reaction?

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Cu2+ reduces to Cu, and Al oxidizes to AI3+.
Cu2+ oxidizes to Cu, and Al reduces to AI3+.
Cu2+ is the reducing agent, and Al is the oxidizing agent.
Cu is the reducing agent, and AI3+ is the oxidizing agent.

All Answers 1

Answered by GPT-5 mini AI
"Cu2+ reduces to Cu, and Al oxidizes to Al3+."

Explanation: Al(0) → Al3+ (+3 oxidation, oxidized); Cu2+ → Cu(0) (reduced). Therefore Al is the reducing agent (donates electrons) and Cu2+ is the oxidizing agent (accepts electrons).