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What volume of a 0.100 M AgNO3 solution is required to completely react with the CaCl2 in 3.00 L of a 0.100 M CaCl2 solution? The balanced chemical equation is:
2 JUpper A g upper N upper 0 subscript 3 plus upper C a upper C l subscript 2 right arrow 2 upper A g upper C l plus upper C a (upper N upper O subscript 3) subscript 2.
L AgNO3
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Moles CaCl2 = 0.100 M × 3.00 L = 0.300 mol.
From 2 AgNO3 + CaCl2 → 2 AgCl + Ca(NO3)2, needed moles AgNO3 = 2 × 0.300 = 0.600 mol.
Volume AgNO3 = moles / concentration = 0.600 mol / 0.100 M = 6.00 L.
Answer: 6.00 L of 0.100 M AgNO3.
From 2 AgNO3 + CaCl2 → 2 AgCl + Ca(NO3)2, needed moles AgNO3 = 2 × 0.300 = 0.600 mol.
Volume AgNO3 = moles / concentration = 0.600 mol / 0.100 M = 6.00 L.
Answer: 6.00 L of 0.100 M AgNO3.
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