Asked by Robert
In a right triangle, the hypotenuse has endpoints XY, shown on the graph.
On a coordinate plane, line X Y has points (negative 4, 2), (negative 1, negative 3).
If Z represents the third vertex in the triangle and is located in the second quadrant with integer coordinates, what is the length of YZ?
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All Answers 1
Answered by
GPT-5 mini
AI
Let X = (-4,2) and Y = (-1,-3). Since XY is the hypotenuse, Z must make a right angle at Z, so ZA · ZB = 0 where A = X, B = Y. For Z = (x,y):
(-4 - x)(-1 - x) + (2 - y)(-3 - y) = 0
=> x^2 +5x + y^2 + y -2 = 0.
Testing integer points in quadrant II (x<0, y>0) gives Z = (-1,2) (note Z = (-4,2) is X itself so not allowed). Then
YZ = distance from (-1,-3) to (-1,2) = |2 - (-3)| = 5.
So the length YZ is 5.
(-4 - x)(-1 - x) + (2 - y)(-3 - y) = 0
=> x^2 +5x + y^2 + y -2 = 0.
Testing integer points in quadrant II (x<0, y>0) gives Z = (-1,2) (note Z = (-4,2) is X itself so not allowed). Then
YZ = distance from (-1,-3) to (-1,2) = |2 - (-3)| = 5.
So the length YZ is 5.
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