Asked by donald
Identify the transformation that best characterizes the graph. Responses The graph shows a reflection over the line y=−1 . The graph shows a reflection over the line y is equal to negative 1. - no response given The graph shows the reflection over the y-axis. The graph shows the reflection over the y-axis. - no response given The graph shows a reflection over the line x=1 . The graph shows a reflection over the line x is equal to 1. - no response given The graph shows a reflection over the x-axis. The graph shows a reflection over the x-axis. - no response given
All Answers 1
Answered by
GPT-5 mini
AI
I don’t see the graph. Could you upload it or describe a few matching point pairs (one point on the pre-image and its corresponding point on the image)?
How to decide (quick rules you can use once you have one matching pair):
- Reflection across the line y = k: a point (x, y) maps to (x, 2k − y). The midpoint’s y-coordinate is k.
- Reflection across the line x = h: a point (x, y) maps to (2h − x, y). The midpoint’s x-coordinate is h.
- Reflection across the y-axis (x = 0): (x, y) maps to (−x, y). Midpoint x = 0.
- Reflection across the x-axis (y = 0): (x, y) maps to (x, −y). Midpoint y = 0.
Procedure:
1. Pick one clear point from the original and its corresponding point on the reflected graph.
2. Compute the midpoint ((x1+x2)/2, (y1+y2)/2).
3. If the midpoint’s x is constant for several pairs, the line x = that value is the reflection line. If the midpoint’s y is constant, the line y = that value is the reflection line.
If you give one or two point pairs (or upload the image), I’ll identify which option is correct.
How to decide (quick rules you can use once you have one matching pair):
- Reflection across the line y = k: a point (x, y) maps to (x, 2k − y). The midpoint’s y-coordinate is k.
- Reflection across the line x = h: a point (x, y) maps to (2h − x, y). The midpoint’s x-coordinate is h.
- Reflection across the y-axis (x = 0): (x, y) maps to (−x, y). Midpoint x = 0.
- Reflection across the x-axis (y = 0): (x, y) maps to (x, −y). Midpoint y = 0.
Procedure:
1. Pick one clear point from the original and its corresponding point on the reflected graph.
2. Compute the midpoint ((x1+x2)/2, (y1+y2)/2).
3. If the midpoint’s x is constant for several pairs, the line x = that value is the reflection line. If the midpoint’s y is constant, the line y = that value is the reflection line.
If you give one or two point pairs (or upload the image), I’ll identify which option is correct.
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