Asked by Johnnie

A child bounces a 46 g superball on the side-walk. The velocity change of the superball isfrom 28 m/s downward to 16 m/s upward.If the contact time with the sidewalk is1800s, what is the magnitude of the average forceexerted on the superball by the sidewalk?
Answer in units of N.
Answered by bobpursley
force*time= mass*changevelocity
= mass*(16-(-28)

find force.
Answered by Johnnie
i got 1.124 nd it said it was wrong

force*1800s=46*44
force*1800s=2024
force=1.12444444
Answered by Phyyswiz
The problem with your answe was that you didn't convert the grams to kg
Answered by Ann
Also it's not 1800, it's 1/800
Answered by Ann
Also it's not 1800, it's 1/800
so it would be: .046kg * 44 = 2.024
2.024/(1/800)

It should equal = 1619.2
Check your answer but that should be it, especially if they're asking you in units of N
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