Asked by Johnnie
A child bounces a 46 g superball on the side-walk. The velocity change of the superball isfrom 28 m/s downward to 16 m/s upward.If the contact time with the sidewalk is1800s, what is the magnitude of the average forceexerted on the superball by the sidewalk?
Answer in units of N.
Answer in units of N.
Answers
Answered by
bobpursley
force*time= mass*changevelocity
= mass*(16-(-28)
find force.
= mass*(16-(-28)
find force.
Answered by
Johnnie
i got 1.124 nd it said it was wrong
force*1800s=46*44
force*1800s=2024
force=1.12444444
force*1800s=46*44
force*1800s=2024
force=1.12444444
Answered by
Phyyswiz
The problem with your answe was that you didn't convert the grams to kg
Answered by
Ann
Also it's not 1800, it's 1/800
Answered by
Ann
Also it's not 1800, it's 1/800
so it would be: .046kg * 44 = 2.024
2.024/(1/800)
It should equal = 1619.2
Check your answer but that should be it, especially if they're asking you in units of N
so it would be: .046kg * 44 = 2.024
2.024/(1/800)
It should equal = 1619.2
Check your answer but that should be it, especially if they're asking you in units of N
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