Question

A volleyball is served from a height of 6 feet with an initial velocity of 33 feet per second. The situation is modeled using the function h=−6t2+33t+6, where h is the height in feet and t is time in seconds.Which of the following uses the function to correctly identify the corresponding y-values to the given x-values of 0, 1, 2, 3, and 4?(1 point)Responses(0, 6), (1, 21), (2, 48), (3, 69), and (4, 90)(0, 6), (1, 21), (2, 48), (3, 69), and (4, 90)(6, 0), (33, 1), (48, 2), (51, 3), and (42, 4)(6, 0), (33, 1), (48, 2), (51, 3), and (42, 4)(0, 6), (1, 33), (2, 48), (3, 51) and (4, 42)(0, 6), (1, 33), (2, 48), (3, 51) and (4, 42)(0, 0), (1, 27), (2, 42), (3, 45), and (4, 36)(0, 0), (1, 27), (2, 42), (3, 45), and (4, 36)

Answer 1

Evaluate h(t) = −6t^2 + 33t + 6 at each t:

t=0: h = 6 → (0, 6)
t=1: h = −6 + 33 + 6 = 33 → (1, 33)
t=2: h = −24 + 66 + 6 = 48 → (2, 48)
t=3: h = −54 + 99 + 6 = 51 → (3, 51)
t=4: h = −96 + 132 + 6 = 42 → (4, 42)

So the correct choice is (0, 6), (1, 33), (2, 48), (3, 51), and (4, 42).