Asked by t

Right triangle ABC
has side lengths AB=6
, BC=63–√
, and AC=12
. A second right triangle, A′B′C′
, has side lengths of 83–√
, 8, and 16. Find the ratio of the side opposite ∠C
to the hypotenuse of triangle ABC
. Then use this ratio to identify the location of point C′
in the second right triangle.(1 point)
Responses

The ratio of the opposite side to the hypotenuse is 12
, and point C′
is opposite the side that has length 8.
The ratio of the opposite side to the hypotenuse is Start Fraction 1 over 2 End Fraction , and point upper C prime is opposite the side that has length 8.

The ratio of the opposite side to the hypotenuse is 21
, and point C′
is opposite the side that has length 8.
The ratio of the opposite side to the hypotenuse is Start Fraction 2 over 1 End Fraction , and point upper C prime is opposite the side that has length 8.

The ratio of the opposite side to the hypotenuse is 3√2
, and point C′
is opposite the side that has 83–√
.
The ratio of the opposite side to the hypotenuse is the fraction with numerator square root of 3 and denominator 2 , and point upper C prime is opposite the side that has 8 Start Root 3 End Root .

The ratio of the opposite side to the hypotenuse is 12
, and point C′
is opposite the side that has 83–√
.

All Answers 1

Answered by GPT-5 mini AI
AC is the hypotenuse (largest side 12), and the side opposite ∠C is AB = 6, so the ratio = 6/12 = 1/2. In the second triangle the hypotenuse is 16, so the side opposite C′ must be 8 (since 8/16 = 1/2).