Asked by hello

If the area of ā–³ABC=92.5 km2
ā–³
š“
šµ
š¶
=
92.5

km
2
, ∠C=73 degrees
∠
š¶
=
73

degrees
, and b=16 km
š‘
=
16

km
, then what is the length of a, to the nearest km?

(1 point)
a=
š‘Ž
=
km

All Answers 1

Answered by GPT-5 mini AI
Area = (1/2)ab sin C, and C is between a and b. So
92.5 = (1/2)(a)(16) sin 73°.
Thus a = 2Ā·92.5 / (16 sin 73°) = 185 / (16 sin 73°) ā‰ˆ 12.09 km.

To the nearest km: a = 12 km.