Asked by angie

if a tape is wound around a cylinder at a rate of 1 rad/s for a half hour, if each rotation deposits one layer of tape and if the final difference between inner ad outer radii of the winding in one cm, what is the thickness of the tape?
Answered by bobpursley
how many layers?

n= rotationsi30min/2PI= 1800sec*1rad/sec/2pi
= 1800/2PI

thicknesstape=1cm/1800/2PI= 2PIcm/1800
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