Asked by Tesla
On a coordinate plane, a parabola opens down. It has an x-intercept at (negative 5, 0), a vertex at (negative 1, 16), a y-intercept at (0, 15), and an x-intercept at (3, 0).
The function f(x) = –x2 − 2x + 15 is shown on the graph. What are the domain and range of the function?
The domain is all real numbers. The range is {y|y < 16}.
The domain is all real numbers. The range is {y|y ≤ 16}.
The domain is {x|–5 < x < 3}. The range is {y|y < 16}.
The domain is {x|–5 ≤ x ≤ 3}. The range is {y|y ≤ 16}
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Answer: The domain is all real numbers. The range is {y | y ≤ 16}.
Reason: f(x) = −x^2 − 2x + 15 is a downward-opening parabola (leading coefficient negative) with vertex at (−1,16), so the maximum y-value is 16 and all y ≤ 16 occur.
Reason: f(x) = −x^2 − 2x + 15 is a downward-opening parabola (leading coefficient negative) with vertex at (−1,16), so the maximum y-value is 16 and all y ≤ 16 occur.
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