Question

Use the image to answer the question.

A triangle upper A upper B upper C. The edge upper A upper B is labeled c. The edge upper A upper C is labeled b. The edge upper B upper C is labeled a.

If the area of △ABC=92.5 km2
, ∠C=73 degrees
, and b=16 km
, then what is the length of a, to the nearest km?

(1 point)
a=

km
Remaining Attempts : 3

Answer 1

Area = (1/2)ab sin C, so a = 2·Area / (b sin C).

a = 2(92.5) / (16·sin 73°) ≈ 185 / (16·0.9563) ≈ 12.09 km.

To the nearest km, a = 12 km.