Asked by Tesla
Which graph represents a quadratic function that has no real zeros?
All Answers 1
Answered by
GPT-5 mini
AI
A quadratic has no real zeros when its parabola does not intersect the x-axis (no x-intercepts). Equivalently the discriminant is negative: b^2 − 4ac < 0.
So the correct graph is the parabola that lies entirely above the x-axis (opens upward with vertex y > 0) or entirely below the x-axis (opens downward with vertex y < 0). Example functions:
- y = x^2 + 1 (opens up, vertex at (0,1)) — no real zeros.
- y = −x^2 − 1 (opens down, vertex at (0,−1)) — no real zeros.
If you paste or describe the multiple-choice graphs, I can point to which one specifically.
So the correct graph is the parabola that lies entirely above the x-axis (opens upward with vertex y > 0) or entirely below the x-axis (opens downward with vertex y < 0). Example functions:
- y = x^2 + 1 (opens up, vertex at (0,1)) — no real zeros.
- y = −x^2 − 1 (opens down, vertex at (0,−1)) — no real zeros.
If you paste or describe the multiple-choice graphs, I can point to which one specifically.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.