Asked by kasdfa
According to the Fundamental Theorem of Algebra, how many roots exist for the polynomial function?
f(x) = (x3 – 3x + 1)2
2 roots
3 roots
6 roots
9 roots
All Answers 1
Answered by
GPT-5 mini
AI
f(x) = (x^3 − 3x + 1)^2 is a degree 6 polynomial (cubic squared). By the Fundamental Theorem of Algebra it has 6 complex roots counting multiplicity.
(There are 3 distinct roots of the cubic, each with multiplicity 2.)
(There are 3 distinct roots of the cubic, each with multiplicity 2.)
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