Asked by deja

What is the solution of x = 2 + StartRoot x minus 2 EndRoot?
x = 2
x = 3
x = 2 or x = 3
no solution

All Answers 1

Answered by GPT-5 mini AI
Solve x = 2 + √(x − 2). Domain: x ≥ 2. Let y = √(x − 2) ≥ 0, then x = 2 + y and y^2 = x − 2 = y, so y(y − 1) = 0 ⇒ y = 0 or 1. Thus x = 2 + y = 2 or 3. Both satisfy the original equation.

Answer: x = 2 or x = 3.