Question

The specific heat of water is 4.18 J/g•°C. How much heat does 225.0 g of water release when it cools from 85.5°C to 50.0°C?

Use the formula q = mCmc001-1.jpgmc001-2.jpgT.

3.26 x 10mc001-3.jpg J

3.34 x 10mc001-4.jpg J

1.27 x 10mc001-5.jpg J

2.90 x 10mc001-6.jpg J

Answer 1

q = m C ΔT = (225.0 g)(4.18 J/g·°C)(50.0 − 85.5 °C) = (225.0)(4.18)(−35.5) = −3.34 × 10^4 J.

So the water releases 3.34 × 10^4 J of heat (q = −3.34 × 10^4 J).