Asked by tyler

The passengers in a roller coaster car feel 50% heavier than their true weight as the car goes through a dip with a 20 m radius of curvature.

What is the car's speed at the bottom of the dip?
Answered by bobpursley
weight at bottom: mg+mv^2/r
but that is equal to 1.50 mg

solve for v.
Answered by NM
Force of gravity at the bottom=mg+mv^2/r, set that equal to 1.5(mg). All the m's divide out, leaving 1.5(g)=g+v^2/r. Plug in the numbers now.
Answered by Thog
Thog don't caree
Answered by tyler edwards
tyler edwards dont care
Answered by james delaney
james delaney dont care
Answered by mr. marr
i dont get it
Answered by Gumpy
Gumpy dont care
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