Asked by tyler
                The passengers in a roller coaster car feel 50% heavier than their true weight as the car goes through a dip with a 20 m radius of curvature.
What is the car's speed at the bottom of the dip?
            
        What is the car's speed at the bottom of the dip?
Answers
                    Answered by
            bobpursley
            
    weight at bottom: mg+mv^2/r
but that is equal to 1.50 mg
solve for v.
    
but that is equal to 1.50 mg
solve for v.
                    Answered by
            NM
            
    Force of gravity at the bottom=mg+mv^2/r, set that equal to 1.5(mg). All the m's divide out, leaving 1.5(g)=g+v^2/r. Plug in the numbers now.
    
                    Answered by
            Thog
            
    Thog don't caree
    
                    Answered by
            tyler edwards
            
    tyler edwards dont care
    
                    Answered by
            james delaney
            
    james delaney dont care
    
                    Answered by
            mr. marr
            
    i dont get it
    
                    Answered by
            Gumpy
            
    Gumpy dont care
    
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.