Asked by tyler
The passengers in a roller coaster car feel 50% heavier than their true weight as the car goes through a dip with a 20 m radius of curvature.
What is the car's speed at the bottom of the dip?
What is the car's speed at the bottom of the dip?
Answers
Answered by
bobpursley
weight at bottom: mg+mv^2/r
but that is equal to 1.50 mg
solve for v.
but that is equal to 1.50 mg
solve for v.
Answered by
NM
Force of gravity at the bottom=mg+mv^2/r, set that equal to 1.5(mg). All the m's divide out, leaving 1.5(g)=g+v^2/r. Plug in the numbers now.
Answered by
Thog
Thog don't caree
Answered by
tyler edwards
tyler edwards dont care
Answered by
james delaney
james delaney dont care
Answered by
mr. marr
i dont get it
Answered by
Gumpy
Gumpy dont care