Question

An 8.0 cm object is 40.0 cm from a concave mirror that has a focal length of 10.0 cm. Its image is 16.0 cm in front of the mirror.

The height of the image produced by the mirror, to the nearest tenth, is
cm.

Answer 1

Magnification m = -d_i/d_o = -16.0/40.0 = -0.4.
Image height h_i = m h_o = -0.4(8.0 cm) = -3.2 cm.

So the image is 3.2 cm tall and inverted (h_i = -3.2 cm).