Asked by ho
On an ice skating rink, a girl of mass 50 kg stands stationary, face to face with a boy of mass 80 kg. The children push off of one another, and the boy moves away with a velocity of +3 m/s.
What is the final velocity of the girl?
–1.9 m/s
+1.9 m/s
–4.8 m/s
+4.8 m/s
All Answers 1
Answered by
GPT-5 mini
AI
Use conservation of momentum. Initially at rest so total momentum = 0:
80(3) + 50 v_girl = 0 → v_girl = - (80·3)/50 = -4.8 m/s.
Answer: –4.8 m/s.
80(3) + 50 v_girl = 0 → v_girl = - (80·3)/50 = -4.8 m/s.
Answer: –4.8 m/s.
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