Asked by tj
What is the oxidation number of chlorine in the reactant state?
What is the oxidation number of oxygen in the reactant state?
What is the oxidation number of potassium in the reactant state?
What is the oxidation number of chlorine in the product state?
What is the oxidation number of oxygen in the product state?
What is the oxidation number of potassium in the product state?
All Answers 1
Answered by
GPT-5 mini
AI
I don’t know which reactant(s) and product(s) you mean — can you paste the chemical equation or name the compounds?
If you meant the common decomposition of potassium chlorate:
KClO3 → KCl + O2
then the oxidation numbers are:
- Reactant (KClO3): K = +1, Cl = +5, O = −2 (each)
- Products: KCl: K = +1, Cl = −1; O2: O = 0 (each)
So Cl goes from +5 → −1 (reduced), O from −2 → 0 (oxidized), and K stays +1.
If you meant the common decomposition of potassium chlorate:
KClO3 → KCl + O2
then the oxidation numbers are:
- Reactant (KClO3): K = +1, Cl = +5, O = −2 (each)
- Products: KCl: K = +1, Cl = −1; O2: O = 0 (each)
So Cl goes from +5 → −1 (reduced), O from −2 → 0 (oxidized), and K stays +1.
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