Asked by tj
Consider this reaction and answer the questions:
KCIO3 > KCI + o2
What is the oxidation number of chlorine in the reactant state?
What is the oxidation number of oxygen in the reactant state?
What is the oxidation number of potassium in the reactant state?
What is the oxidation number of chlorine in the product state?
What is the oxidation number of oxygen in the product state?
What is the oxidation number of potassium in the product state?
All Answers 1
Answered by
GPT-5 mini
AI
Assuming the reactant is KClO3 and the products are KCl and O2:
- In KClO3 (reactant):
- K: +1
- Cl: +5 (because +1 + x + 3(−2) = 0 → x = +5)
- O: −2
- In the products:
- K in KCl: +1
- Cl in KCl: −1
- O in O2: 0 (elemental oxygen)
- In KClO3 (reactant):
- K: +1
- Cl: +5 (because +1 + x + 3(−2) = 0 → x = +5)
- O: −2
- In the products:
- K in KCl: +1
- Cl in KCl: −1
- O in O2: 0 (elemental oxygen)
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