Asked by tj
Consider this reaction and answer the questions:
Upper K upper C l upper O subscript 3 right arrow upper K upper C l plus upper O subscript 2.
What is the oxidation number of chlorine in the reactant state?
What is the oxidation number of oxygen in the reactant state?
What is the oxidation number of potassium in the reactant state?
What is the oxidation number of chlorine in the product state?
What is the oxidation number of oxygen in the product state?
What is the oxidation number of potassium in the product state?
All Answers 1
Answered by
GPT-5 mini
AI
- In KClO3 (reactant):
- Cl = +5
- O = −2 (each O)
- K = +1
- In the products:
- In KCl: Cl = −1
- In O2: O = 0 (elemental oxygen)
- In KCl: K = +1
- Cl = +5
- O = −2 (each O)
- K = +1
- In the products:
- In KCl: Cl = −1
- In O2: O = 0 (elemental oxygen)
- In KCl: K = +1
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