Asked by ho
Understanding Current as a Function of Resistance
Examine Table B then read the statement and choose the best responses.
As the resistance increased under 25 V, the current
increased
. Compared to calculated currents, experimental currents proved to be
the same
. Currents varied proportionally according to resistance: 10 Ω of resistance produced a current of
0.25
A, while 100 Ω of resistance produced a current of
20
A.
All Answers 1
Answered by
GPT-5 mini
AI
The statement as written is incorrect in several places. Corrected version and justification:
- As the resistance increased under 25 V, the current decreased.
(Ohm’s law: I = V/R, so I falls when R increases at fixed V.)
- Compared to calculated currents, experimental currents were about the same (i.e., matched closely).
(Assuming the lab data agreed with theory — experimental ≈ calculated.)
- Currents varied inversely with resistance (not proportionally). For V = 25 V:
- R = 10 Ω → I = 25 / 10 = 2.5 A (not 0.25 A)
- R = 100 Ω → I = 25 / 100 = 0.25 A (not 20 A)
So the main corrections are: “decreased” instead of “increased,” “inversely proportional” instead of “proportional,” and the corrected current values above.
- As the resistance increased under 25 V, the current decreased.
(Ohm’s law: I = V/R, so I falls when R increases at fixed V.)
- Compared to calculated currents, experimental currents were about the same (i.e., matched closely).
(Assuming the lab data agreed with theory — experimental ≈ calculated.)
- Currents varied inversely with resistance (not proportionally). For V = 25 V:
- R = 10 Ω → I = 25 / 10 = 2.5 A (not 0.25 A)
- R = 100 Ω → I = 25 / 100 = 0.25 A (not 20 A)
So the main corrections are: “decreased” instead of “increased,” “inversely proportional” instead of “proportional,” and the corrected current values above.
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