Asked by Physics: energy
The CoolWheels Toy Company is designing a new track where a car (mass 60 g) is launched by a spring-loaded starter (k=11 N/m) and goes through a vertical loop (radius 9 cm). If the spring is depressed ∆x=19 cm from equilibrium, what is the speed of the car at the top of the loop?
Answers
Answered by
bobpursley
initial PEspring-changePE top= final KE
1/2 11*.19^2 - .060g*.18=1/2*.060v^2 solve for v.
1/2 11*.19^2 - .060g*.18=1/2*.060v^2 solve for v.
Answered by
molly
Thank you
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