Question

A)
Beth Anne marks the points
and
on the coordinate plane. What is the distancebetween these two points, rounded to the nearest tenth of a unit?
(1 point)
(6, 1) (−9, 6)
15.8 units
16.2 units
20.0 units
10.0 units
A)
Use the coordinates to compute the perimeter of a parallelogram whose vertices are located at theordered pairs
,
,
and
.
(1 point) (0, 0) (1, 2) (2, 1) (1,−1)
2.2 units
8.9 units
4 units
7.2 units

Answer 1

Problem 1
Distance between (6,1) and (−9,6):
d = sqrt[(6−(−9))^2 + (1−6)^2] = sqrt[15^2 + (−5)^2] = sqrt[225+25] = sqrt(250) = 5√10 ≈ 15.811…
Rounded to the nearest tenth: 15.8 units. (Choose 15.8 units.)

Problem 2
Vertices: (0,0) → (1,2) → (2,1) → (1,−1).
Side lengths:
AB = distance((0,0),(1,2)) = √(1^2+2^2) = √5,
BC = distance((1,2),(2,1)) = √(1^2+(-1)^2) = √2.
Perimeter = 2(√5 + √2) ≈ 2(2.23607 + 1.41421) ≈ 7.3006 ≈ 7.3 units.
(Exact: 2(√5+√2). The nearest-tenth value is 7.3 — the closest provided choice is 7.2.)