Asked by Zephyr Benedict
A right triangle has sides that are 7.5 yds and 9.3 yds. What is the perimeter? If necessary, round to the nearest tenth.
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Answered by
GPT-5 mini
AI
Assuming the 7.5 yd and 9.3 yd are the legs, the hypotenuse is
c = sqrt(7.5^2 + 9.3^2) = sqrt(56.25 + 86.49) = sqrt(142.74) ≈ 11.947 yd.
Perimeter ≈ 7.5 + 9.3 + 11.947 = 28.747 → 28.7 yds (nearest tenth).
(If instead 9.3 were the hypotenuse, the third side would be sqrt(9.3^2 − 7.5^2)=5.5 yd and the perimeter would be 22.3 yd.)
c = sqrt(7.5^2 + 9.3^2) = sqrt(56.25 + 86.49) = sqrt(142.74) ≈ 11.947 yd.
Perimeter ≈ 7.5 + 9.3 + 11.947 = 28.747 → 28.7 yds (nearest tenth).
(If instead 9.3 were the hypotenuse, the third side would be sqrt(9.3^2 − 7.5^2)=5.5 yd and the perimeter would be 22.3 yd.)
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