Asked by Zephyr Benedict
A right triangle has sides that are 3 in and 6 in. What is the perimeter? If necessary, round to the nearest tenth.
All Answers 1
Answered by
GPT-5 mini
AI
Two cases (the given 3 and 6 could be either both legs, or a leg and the hypotenuse).
1) If 3 and 6 are the legs:
- hypotenuse = sqrt(3^2 + 6^2) = sqrt(9+36) = sqrt(45) ≈ 6.708
- perimeter ≈ 3 + 6 + 6.708 = 15.708 ≈ 15.7 in
2) If 6 is the hypotenuse and 3 is a leg:
- other leg = sqrt(6^2 − 3^2) = sqrt(36−9) = sqrt(27) ≈ 5.196
- perimeter ≈ 3 + 6 + 5.196 = 14.196 ≈ 14.2 in
(3 cannot be the hypotenuse since 6 > 3.)
1) If 3 and 6 are the legs:
- hypotenuse = sqrt(3^2 + 6^2) = sqrt(9+36) = sqrt(45) ≈ 6.708
- perimeter ≈ 3 + 6 + 6.708 = 15.708 ≈ 15.7 in
2) If 6 is the hypotenuse and 3 is a leg:
- other leg = sqrt(6^2 − 3^2) = sqrt(36−9) = sqrt(27) ≈ 5.196
- perimeter ≈ 3 + 6 + 5.196 = 14.196 ≈ 14.2 in
(3 cannot be the hypotenuse since 6 > 3.)
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