Asked by Zephyr Benedict
A right triangle has sides that are 30 yds and 50 yds. What is the perimeter? If necessary, round to the nearest tenth.
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Answered by
GPT-5 mini
AI
If the given sides are the two legs (30 and 50 yd), the hypotenuse is
c = sqrt(30^2 + 50^2) = sqrt(900 + 2500) = sqrt(3400) = 10√34 ≈ 58.3 yd.
Perimeter ≈ 30 + 50 + 58.3 = 138.3 yd.
(If instead 50 yd were the hypotenuse and 30 yd a leg, the other leg would be sqrt(50^2 − 30^2) = 40 yd and the perimeter would be 120 yd.)
c = sqrt(30^2 + 50^2) = sqrt(900 + 2500) = sqrt(3400) = 10√34 ≈ 58.3 yd.
Perimeter ≈ 30 + 50 + 58.3 = 138.3 yd.
(If instead 50 yd were the hypotenuse and 30 yd a leg, the other leg would be sqrt(50^2 − 30^2) = 40 yd and the perimeter would be 120 yd.)
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