Question

If a heat engine is operating between two temperatures (
Q
H
>
Q
C
), what is the maximum efficiency attainable?(1 point)
Responses

Q
C
−
Q
H

upper Q subscript upper C baseline minus upper Q subscript upper H baseline

1
−
Q
C
Q
H

1 minus Start Fraction upper Q subscript upper C baseline over upper Q subscript upper H baseline End Fraction

1
−
Q
H
Q
C

1 minus Start Fraction upper Q subscript upper H baseline over upper Q subscript upper C baseline End Fraction

Q
H
−
Q
C

upper Q subscript upper H baseline minus upper Q subscript upper C baseline
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Answer 1

1 − Q_C/Q_H

(Equivalently η = (Q_H − Q_C)/Q_H; the maximum for a reversible/Carnot engine is η = 1 − T_C/T_H, which in terms of heats here is 1 − Q_C/Q_H.)