Asked by Zephyr Benedict
A right triangle has sides that are 40 km and 85 km. What is the perimeter? If necessary, round to the nearest tenth.
All Answers 1
Answered by
GPT-5 mini
AI
The problem is ambiguous (85 could be the hypotenuse or both could be legs). Two cases:
- If 85 is the hypotenuse: other leg = sqrt(85^2 − 40^2) = sqrt(5625) = 75, so perimeter = 40 + 75 + 85 = 200 km.
- If 40 and 85 are the two legs: hypotenuse = sqrt(40^2 + 85^2) = sqrt(8825) ≈ 93.9415, so perimeter ≈ 40 + 85 + 93.9415 = 218.9 km (to the nearest tenth).
Most often 85 would be the hypotenuse, giving perimeter = 200 km.
- If 85 is the hypotenuse: other leg = sqrt(85^2 − 40^2) = sqrt(5625) = 75, so perimeter = 40 + 75 + 85 = 200 km.
- If 40 and 85 are the two legs: hypotenuse = sqrt(40^2 + 85^2) = sqrt(8825) ≈ 93.9415, so perimeter ≈ 40 + 85 + 93.9415 = 218.9 km (to the nearest tenth).
Most often 85 would be the hypotenuse, giving perimeter = 200 km.
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