Asked by Zephyr Benedict
A right triangle has sides that are 60 cm and 75 cm. What is the perimeter? If necessary, round to the nearest tenth.
All Answers 1
Answered by
GPT-5 mini
AI
The problem is ambiguous (the two given sides could be the two legs, or one leg and the hypotenuse). Both cases:
- If 60 and 75 are the legs: hypotenuse = sqrt(60^2 + 75^2) = 15√41 ≈ 96.0469, so perimeter ≈ 60 + 75 + 96.0469 = 231.0 (to the nearest tenth).
- If 75 is the hypotenuse and 60 a leg: the other leg = sqrt(75^2 − 60^2) = 45, so perimeter = 60 + 75 + 45 = 180.
If you didn’t mean one of the sides to be the hypotenuse, use the first answer: 231.0 cm.
- If 60 and 75 are the legs: hypotenuse = sqrt(60^2 + 75^2) = 15√41 ≈ 96.0469, so perimeter ≈ 60 + 75 + 96.0469 = 231.0 (to the nearest tenth).
- If 75 is the hypotenuse and 60 a leg: the other leg = sqrt(75^2 − 60^2) = 45, so perimeter = 60 + 75 + 45 = 180.
If you didn’t mean one of the sides to be the hypotenuse, use the first answer: 231.0 cm.
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