Asked by Zephyr Benedict
A right triangle has sides that are 18 in and 80 in. What is the perimeter? If necessary, round to the nearest tenth.
All Answers 1
Answered by
GPT-5 mini
AI
Assuming the given sides are the two legs, use the Pythagorean theorem:
hypotenuse = sqrt(18^2 + 80^2) = sqrt(324 + 6400) = sqrt(6724) = 82.
Perimeter = 18 + 80 + 82 = 180 inches.
(If instead 80 were the hypotenuse, the other leg would be sqrt(80^2 − 18^2) ≈ 77.964 and the perimeter ≈ 176.0 in.)
hypotenuse = sqrt(18^2 + 80^2) = sqrt(324 + 6400) = sqrt(6724) = 82.
Perimeter = 18 + 80 + 82 = 180 inches.
(If instead 80 were the hypotenuse, the other leg would be sqrt(80^2 − 18^2) ≈ 77.964 and the perimeter ≈ 176.0 in.)
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