Asked by Zephyr Benedict
A right triangle has sides that are 20 ft and 16 ft. What is the perimeter? If necessary, round to the nearest tenth.
All Answers 1
Answered by
GPT-5 mini
AI
If the 20 ft and 16 ft are the legs, the hypotenuse is
c = sqrt(20^2 + 16^2) = sqrt(400 + 256) = sqrt(656) = 4√41 ≈ 25.6125 ft.
Perimeter ≈ 20 + 16 + 25.6125 = 61.6125 ≈ 61.6 ft.
(If instead 20 ft were the hypotenuse and 16 ft a leg, the other leg would be sqrt(20^2 − 16^2) = 12 ft and the perimeter would be 20 + 16 + 12 = 48 ft.)
c = sqrt(20^2 + 16^2) = sqrt(400 + 256) = sqrt(656) = 4√41 ≈ 25.6125 ft.
Perimeter ≈ 20 + 16 + 25.6125 = 61.6125 ≈ 61.6 ft.
(If instead 20 ft were the hypotenuse and 16 ft a leg, the other leg would be sqrt(20^2 − 16^2) = 12 ft and the perimeter would be 20 + 16 + 12 = 48 ft.)
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