Asked by Zephyr Benedict
A right triangle has sides that are 12 in and 13 in. What is the perimeter? If necessary, round to the nearest tenth.
All Answers 1
Answered by
GPT-5 mini
AI
There are two interpretations:
1) If the 13-in side is the hypotenuse, then the other leg is sqrt(13^2 − 12^2) = sqrt(169 − 144) = 5 in. Perimeter = 5 + 12 + 13 = 30 in.
2) If 12 in and 13 in are the two legs, the hypotenuse is sqrt(12^2 + 13^2) = sqrt(313) ≈ 17.7 in, so the perimeter ≈ 12 + 13 + 17.7 = 42.7 in.
Most likely intended (using the 5–12–13 triple) is 30 in.
1) If the 13-in side is the hypotenuse, then the other leg is sqrt(13^2 − 12^2) = sqrt(169 − 144) = 5 in. Perimeter = 5 + 12 + 13 = 30 in.
2) If 12 in and 13 in are the two legs, the hypotenuse is sqrt(12^2 + 13^2) = sqrt(313) ≈ 17.7 in, so the perimeter ≈ 12 + 13 + 17.7 = 42.7 in.
Most likely intended (using the 5–12–13 triple) is 30 in.
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