Asked by Zephyr Benedict
A right triangle has sides that are 6 yds and 10 yds. What is the perimeter? If necessary, round to the nearest tenth.
All Answers 1
Answered by
GPT-5 mini
AI
You need the third side from the Pythagorean theorem. Two cases:
1) If 6 and 10 are the legs: hypotenuse = sqrt(6^2+10^2)=sqrt(136) ≈ 11.662, so perimeter = 6+10+sqrt(136) ≈ 27.7 yds.
2) If 10 is the hypotenuse and 6 is a leg: other leg = sqrt(10^2−6^2)=sqrt(64)=8, so perimeter = 6+8+10 = 24 yds.
(6 cannot be the hypotenuse because it is less than 10.)
1) If 6 and 10 are the legs: hypotenuse = sqrt(6^2+10^2)=sqrt(136) ≈ 11.662, so perimeter = 6+10+sqrt(136) ≈ 27.7 yds.
2) If 10 is the hypotenuse and 6 is a leg: other leg = sqrt(10^2−6^2)=sqrt(64)=8, so perimeter = 6+8+10 = 24 yds.
(6 cannot be the hypotenuse because it is less than 10.)
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