Question

In this part of the experiment, you will be changing the speed of the bottle by dropping it from different heights. You will use the same mass, 0.250 kg, for each trial, so record this mass in Table B for each velocity. Then, calculate the expected kinetic energy (KE) at each velocity. Use the formula KE = one half.mv2,

where m is the mass and v is the speed. Record your calculations in Table B of your Student Guide.

When the speed of the bottle is 2 m/s, the KE is

kg m2/s2.

When the speed of the bottle is 3 m/s, the KE is

kg m2/s2.

When the speed of the bottle is 4 m/s, the KE is

kg m2/s2.

When the speed of the bottle is 5 m/s, the KE is

kg m2/s2.

When the speed of the bottle is 6 m/s, the KE is

kg m2/s2.

Answer 1

Mass for each trial: m = 0.250 kg.

KE = 1/2 m v^2 = 0.125 v^2 (J).

- v = 2 m/s: KE = 0.125(2^2) = 0.500 J (0.500 kg·m^2/s^2).
- v = 3 m/s: KE = 0.125(3^2) = 1.125 J (1.125 kg·m^2/s^2).
- v = 4 m/s: KE = 0.125(4^2) = 2.000 J (2.000 kg·m^2/s^2).
- v = 5 m/s: KE = 0.125(5^2) = 3.125 J (3.125 kg·m^2/s^2).
- v = 6 m/s: KE = 0.125(6^2) = 4.500 J (4.500 kg·m^2/s^2).