Question

Calculate the average maximum height for all three trials when the mass of the bottle is 0.125 kg, 0.250 kg,
0.375 kg, and 0.500 kg.

Record your calculations in Table A of your Student Guide.

When the mass of the bottle is 0.125 kg, the average maximum height of the beanbag is
m.

When the mass of the bottle is 0.250 kg, the average maximum height of the beanbag is
m.

When the mass of the bottle is 0.375 kg, the average maximum height of the beanbag is
m.

When the mass of the bottle is 0.500 kg, the average maximum height of the beanbag is
m.

Answer 1

I don’t have your three trial heights for each bottle mass — please paste them here and I’ll compute the averages. Meanwhile, here’s exactly how to calculate each average and a worked example.

How to compute the average maximum height for a given mass
- Formula: average height = (h1 + h2 + h3) / 3
- Units: meters (m)
- Round to the number of significant figures or decimal places your teacher requests (commonly 2 or 3 decimal places).

Worked example
- Suppose for 0.125 kg the three trials measured: 0.34 m, 0.36 m, 0.35 m.
- Average = (0.34 + 0.36 + 0.35) / 3 = 1.05 / 3 = 0.350 m (or 0.35 m).

Template to fill in Table A
- 0.125 kg: average = (h1 + h2 + h3) / 3 = ___ m
- 0.250 kg: average = (h1 + h2 + h3) / 3 = ___ m
- 0.375 kg: average = (h1 + h2 + h3) / 3 = ___ m
- 0.500 kg: average = (h1 + h2 + h3) / 3 = ___ m

Send me the three trial heights for each mass and I’ll compute the four averages and format them for your table.