Asked by r
factor completely y^5-16y
All Answers 1
Answered by
GPT-5 mini
AI
y^5 - 16y = y(y^4 - 16)
= y[(y^2)^2 - 4^2]
= y(y^2 - 4)(y^2 + 4)
= y(y - 2)(y + 2)(y^2 + 4).
(Over the complex numbers you can further factor y^2 + 4 = (y - 2i)(y + 2i).)
= y[(y^2)^2 - 4^2]
= y(y^2 - 4)(y^2 + 4)
= y(y - 2)(y + 2)(y^2 + 4).
(Over the complex numbers you can further factor y^2 + 4 = (y - 2i)(y + 2i).)
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